Log(4x+1)=log(x^2)+4

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Solution for Log(4x+1)=log(x^2)+4 equation: 


Simplifying
Log(4x + 1) = log(x2) + 4

Reorder the terms:
goL(1 + 4x) = log(x2) + 4
(1 * goL + 4x * goL) = log(x2) + 4
(1goL + 4goxL) = log(x2) + 4

Multiply glo * x2
1goL + 4goxL = glox2 + 4

Reorder the terms:
1goL + 4goxL = 4 + glox2

Solving
1goL + 4goxL = 4 + glox2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1glox2' to each side of the equation.
1goL + -1glox2 + 4goxL = 4 + glox2 + -1glox2

Reorder the terms:
-1glox2 + 1goL + 4goxL = 4 + glox2 + -1glox2

Combine like terms: glox2 + -1glox2 = 0
-1glox2 + 1goL + 4goxL = 4 + 0
-1glox2 + 1goL + 4goxL = 4

Reorder the terms:
-4 + -1glox2 + 1goL + 4goxL = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + -1glox2 + 1goL + 4goxL = 0

The solution to this equation could not be determined.

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